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(12f^2-9f+15)-(-4f^2-3f=6f)
We move all terms to the left:
(12f^2-9f+15)-(-4f^2-3f-(6f))=0
We get rid of parentheses
4f^2+12f^2+3f+6f-9f+15=0
We add all the numbers together, and all the variables
16f^2+15=0
a = 16; b = 0; c = +15;
Δ = b2-4ac
Δ = 02-4·16·15
Δ = -960
Delta is less than zero, so there is no solution for the equation
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